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Calc 1 3.6

 

<== Calculus 1
Number Question Answer
See the work
1. Find the numerical value of the expression:
sinh1
1.1752011936438
The work

Point Cost: 2
2. Find the numerical value of the expression:
cosh1
1.54308063481524
The work

Point Cost: 2
3. Find the numerical value of the expression:
tanh3
0.995054753686731
The work

Point Cost: 2
4. Find the numerical value of the expression:
cosh(ln4)
2.125
The work

Point Cost: 2

5.

Find the numerical value of the expression:
sech(5)
0.0134752822213046
The work

Point Cost: 2

6.

 

Find the derivative of
ƒ(x) = tanh(6x):
ƒ'(x)=
ƒ'(x)= 6(sech(6x))^2
The work

Point Cost: 2

7.

 

Find the derivative of
ƒ(x)= sinh^2x:
ƒ'(x)=_____
ƒ'(x)=2sinh(x)*cosh(x)
The work

Point Cost: 2

8.

 

Find the derivative of
ƒ(x)= sinh(x^3+3):
ƒ'(x)=______
ƒ'(x)=3x^(2)*cosh(x^3+3)
The work

Point Cost: 2

9.

 

Find the derivative of
ƒ(x)= sinh(x) tanh(x):
ƒ'(x)=
ƒ'(x)= sinh(x)*(sech(x))^2+ tanh(x)*(cosh(x))
The work

Point Cost: 2

10.

 

Find the derivative of
ƒ(x) =
(4-cosh(x))/(4+cosh(x)).
ƒ'(x)=________
ƒ'(x)= -2*4*sinh(x)/(4+cosh(x))ˆ2
The work

Point Cost: 2

11.

 

Find the derivative of
ƒ(t)= e^tsech(t):
ƒ'(t)=______
ƒ'(t)= e^(t)*(-sech(t))*tanh(t)+ sech(t)*exp(t)
The work

Point Cost: 2

12.

 

Find the derivative of
ƒ(t)= ln(sinh(t)):
ƒ'(t)=_____
ƒ'(t)= cosh(t)/sinh(t)
The work

Point Cost: 2

13.

 

Find the derivative of
ƒ(x)= x^3 cosh(x^4):
ƒ'(x)=________
ƒ'(x)=(3x^(2))*cosh(x^4)+ (x^3)*sinh(x^4)(4x^(3))
The work

Point Cost: 2
14. Find the derivative of
ƒ(t)= tanh(e^t):
ƒ'(t)=______
ƒ'(t)= e^(t)*(sech(exp(t)))^2
The work

Point Cost: 2

15.

 

Find the derivative of
ƒ(x)=sinh(cosh(x)):
ƒ'(x)=_____

ƒ'(x)= cosh(cosh(x))*sinh(x)
The work

Point Cost: 2
16. Find the derivative of
ƒ(x)= e^(2cosh(8x))
ƒ'(x)=_____
ƒ'(x)=8*2*(sinh(8*x))*e^(2*cosh(8*x))
The work

Point Cost: 2